What is the value of this expression? 6⋅[(32−8)÷4 2]

                  6⋅[(32−8)÷4+2]= 48

While solving an arithmetic expression we use the PEMDAS rule which is an acronym for Parentheses,exponent,Multiplication,Division,Addition and Subtraction.

i.e. it says that the parentheses term should be given most preference while solving and arithmetic expression, then after that the preference is given to exponent term, then to multiplication term, then to division  and addition and subtraction are treated at the same level.

Here we have the expression as:

          6⋅[(32−8)÷4+2]

We first solve the parentheses term.

i.e. 32-8=24

Now, 24÷4=6

Hence, the expression becomes:

6⋅[(32−8)÷4+2]=6·[6+2]

i.e.

6⋅[(32−8)÷4+2]=6·8

Hence, we have:

             6⋅[(32−8)÷4+2]= 48

answer: (1,3) and (-2,0) i think.

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2