Please help me compute the standard deviation! What is the income distribution of super shoppers. in the following table, income units are in thousands of dollars, and each interval goes up to but does not include the given high value. the midpoint are given to the nearest thousand dollars. income range: 5-15, 15-25, 25-35, 35-45, 45-55, 55 or more. next line is midpoint x: 10, 20, 30, 40, 50, 60. last line is percent of super shoppers: 21%, 14%, 22%, 15%, 20%, 8%. part (d): compute the standard deviation

Brent wants to know what is 5 x 1/2

Drag each equation to the correct location on the table. for each equation, determine the number of solutions and place on the appropriate field in the table.

1. why is a frequency distribution useful? it allows researchers to see the "shape" of the data. it tells researchers how often the mean occurs in a set of data. it can visually identify the mean. it ignores outliers. 2. the is defined by its mean and standard deviation alone. normal distribution frequency distribution median distribution marginal distribution 3. approximately % of the data in a given sample falls within three standard deviations of the mean if it is normally distributed. 95 68 34 99 4. a data set is said to be if the mean of the data is greater than the median of the data. normally distributed frequency distributed right-skewed left-skewed