Factor 10 h + 30 + 50 j 10h+30+50j10, h, plus, 30, plus, 50, j to identify the equivalent expressions. Choose 2 answers: Choose 2 answers: (Choice A) A 5 ( 2 h + 30 + 50 j ) 5(2h+30+50j)5, left parenthesis, 2, h, plus, 30, plus, 50, j, right parenthesis (Choice B) B 10 ( h + 3 + 5 j ) 10(h+3+5j)10, left parenthesis, h, plus, 3, plus, 5, j, right parenthesis (Choice C) C 2 ( 5 h + 15 + 25 j ) 2(5h+15+25j)2, left parenthesis, 5, h, plus, 15, plus, 25, j, right parenthesis (Choice D) D 15 ( 10 h + 2 + 50 j ) 15(10h+2+50j)

(Choice B) B 10 ( h + 3 + 5 j ) 10(h+3+5j)10, left parenthesis, h, plus, 3, plus, 5, j, right parenthesis

(Choice C) C 2 ( 5 h + 15 + 25 j ) 2(5h+15+25j)2, left parenthesis, 5, h, plus, 15, plus, 25, j, right parenthesis

Step-by-step explanation:

10h+30+50j

There are two answers

First answer

Factorise using 10 as common factor

10h+30+50j

=10(h+3+5j)

(Choice B) B 10 ( h + 3 + 5 j ) 10(h+3+5j)10, left parenthesis, h, plus, 3, plus, 5, j, right parenthesis

Second answer

Factorise using 2 as the common factor

10h+30+50j

=2(5h+15+25j)

(Choice C) C 2 ( 5 h + 15 + 25 j ) 2(5h+15+25j)2, left parenthesis, 5, h, plus, 15, plus, 25, j, right parenthesis

answer: x=60

80° is the measure of gh

step-by-step explanation:

circle f is congruent to circle j

we have two circle with center f and j.

both circles are congruent. the radius of the circle would be equal.

see the attachment for the circle.

we are given ∠efd ≅ ∠gjh

therefore, arc (ed) = arc (gh)     (∴ circle f is congruent to circle j)

but ∠dfe=80°=arc (ed)

therefore, arc (gh) = 80°

thus, 80° is the measure of gh