If the selected consumer is 70 years old, what is the probability that he/she likes crunchicles

The probability that a selected consumer, given that is 70 years old, likes Crunchicles is 12.78%.

Step-by-step explanation:

The question is incomplete:

Three hundred consumers were surveyed about a new brand of snack food, Crunchicles. Their age groups and preferences are given in the table.

                           18–2425–3435–5555 and overTotal

Liked Crunchicles  4      9       323                  39

Disliked Crunchicles5        27      2864              124

No Preference         7        27          1093                 137

Total                        16        63      41180            300

One consumer from the survey is selected at random. If the selected consumer is 70 years old, what is the probability that he/she likes crunchicles .

If the consumer is 70 years old is included in the category "55 and over" from this survey. There are 180 subjects in that category.

The number that likes Crunchicles and are 55 and over is 23.

If we calculate the probability as the relative frequency, we have:

L: Likes Crunchicles.

The probability that a selected consumer, given that is 70 years old, likes Crunchicles is 12.78%.

16 is the absolute value

step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)