A paper manufacturer packages twelve reams of paper in a box—in three stacks of four reams. A ream of paper weighs 5 pounds and has dimensions of 8.5 inches by 11 inches by 2 inches. Identify three unique ways to package the paper given the new weight condition. Include both the dimensions of the new boxes, as well as a verbal description of how the reams will be packaged. You may include sketches if you wish. I need three ways

The three ways are;

1) Two stacks of six reams

2) Four stacks of three reams

3) Four stacks of three reams arranged two by two

Step-by-step explanation:

The parameters given are;

Dimensions of one ream of paper = 8.5 in. by 11 in. by 2 in.

The number of reams of paper = 12

The three unique ways are;

1) Two stacks of six reams

Box dimension = 6 × 2 in. by 2 × 8.5 in. by 11 in. = 12 in. by 17 in. by 11 in.

Box dimension of new box = 12 in. by 17 in. by 11 in.

2) Four stacks of three reams

Box dimension = 3 × 2 in. by 4 × 8.5 in. by 11 in. = 6 in. by 34 in. by 11 in.

Box dimension of new box = 6 in. by 34 in. by 11 in.

3) Four stacks of three reams arranged two by two

Box dimension = 3 × 2 in. by 2 × 8.5 in. by 2 × 11 in. = 6 in. by 17 in. by 22 in.

Box dimension of new box = 6 in. by 17 in. by 22 in.

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb

62.5 paisa

step-by-step explanation:

4000*70 = 280000

280000-(2000*90) = 100000

4000-2400 = 1600

100000/1600 = 62.5

( give brainliest)