In a bag with 3 red chips, 2 yellow chips, and 1 green chip, what is the probability of getting NO yellow chips on the first 2 tries? A. 1/3 B. 2/3 C. 2/5 D. 3/5

B.

Step-by-step explanation:

total chips = 6

chips not including yellow= 4

simplify 4/6 = 2/3

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.