ΔEFI is dilated by a scale factor of one third with the center of dilation at point F. Then, it is reflected over line a to create ΔHFG. Based on these transformations, which statement is true? Line segments EG and HI intersect at point F, forming triangles EFI and HFG. Line a intersects with both triangles at point F.

segment FE = segment FH over 3, segment FI = segment FG over 3, and segment EI = segment HG over 3; ΔEFI ~ ΔHFG

segment FE = segment FG over 3, segment FI = segment FH over 3, and segment EI = segment HG over 3; ΔEFI ~ ΔGFH

segment FE over 3 = segment FG, segment FI over 3 = segment FH, and segment EI over 3 = segment HG; ΔEFI ~ ΔGFH

segment FE over 3 = segment FH, segment FI over 3 = segment FG, and segment EI over 3 = segment HG; ΔEFI ~ ΔHFG

If ΔEFI is dilated by using a scale factor of 1/3 with the center of dilation at point F, which is reflected over a line to create ΔHFG, the statement that is true about this transformation is:

D. , , ; ΔEFI ~ ΔHFG

Recall:

Scale factor of dilation of ΔEFI, which is reflected over point F to get ΔHFG is given as: 1/3.

Therefore,

FH = 1/3(FE)

HG = 1/3(EI)

FG = 1/3(FI)

Also, since the same shape is maintained, ΔEFI ~ ΔHFG

Therefore, if ΔEFI is dilated by using a scale factor of 1/3 with the center of dilation at point F, which is reflected over a line to create ΔHFG, the statement that is true about this transformation is:

D. , , ; ΔEFI ~ ΔHFG

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The correct option is;

Segment FE over 3 = Segment FH

Segment FI over 3 = Segment FG, and

Segment EI over 3 = Segment HG

ΔEFI ~ ΔHFG

Step-by-step explanation:

The given transformations are'

ΔEFI is dilated by a scale factor of 1/3 and then it is reflected over line a

By dilation, we have

FH = 1/3×FE

FG = 1/3×FI

HG = 1/3×EI

Also by reflection over a line, the relative positions of the y-coordinates of the points remain the same while the x coordinates changes sign such that an upright mirror image of the dilated triangle is formed

Therefore, since we have;

the same for both triangles, that is given the following relation;

FG/FH = (1/3×FI)/(1/3×FE) = FI/FE

Then, ΔEFI is similar to ΔHFG (triangle similarity requirement AAA)

Hence, the correct option is that the

Segment FE over 3 = Segment FH

Segment FI over 3 = Segment FG, and

Segment EI over 3 = Segment HG

ΔEFI ~ ΔHFG.

3: 2

step-by-step explanation:

shorter piece is 2: 3, so just reverse it, and you get 3: 2

a) one student is chosen from classroom a, then a student is chosen from classroom b.  

step-by-step explanation:

independent events are ones in which the probability of one event does not affect the probability of the second event.

one student is chosen from classroom a; this does not affect the chances of choosing a student from classroom b.   this makes these independent events.

when one card is chosen from a standard deck and then set aside before a second card is chosen, the probability of the second card being chosen changes.   this makes them dependent events.

when one student is chosen from classroom a and then a second student is chosen from classroom a, the probability of choosing the second student changes.   this makes them dependent events.

when a letter is chosen from the alphabet and then a second letter is chosen, the probability of choosing the second letter changes.   this makes them dependent events.