What is the vertex of the quadratic function below?
y = 3x2 - 12x+17

D (2, 5)

Step-by-step explanation:

To find the vertex of the quadratic function , we will follow the steps below

(x,y) =  [-b/2a  , f(-b/2a)]

x = -b /2a         y = f(-b/2a)

The standard equation of a quadratic equation is  y =ax² + bx + c

compare the above with the equation given, y = 3x² - 12x + 17

a = 3   b= -12   and c= 17

x = -b/2a

x = -(-12)/2(3)

x = 12/6

x = 2

y = f(-b/2a)

y = f (-b/2a) = f(x) = f (2)

y = f(x) =3x² - 12x + 17

To find f(2) simply mean to substitute x = 2 into the quadratic function above. That is;

f(2) = 3(2)² - 12(2) + 17

f(2) =12-24 + 17

f(2) =5

x = 2   and    y  = 5

(x,y)  = (2, 5)

complete the steps to find the area of the trapezoid.

area of rectangle = 256   square units

area of triangle 1 = 24  square units

area of triangle 2 = 16  square units

area of triangle 3 =   96 square units

area of trapezoid = 120  square units

step-by-step explanation:

50

step-by-step explanation: