The population P of a culture of Pseudomonas aeruginosa bacteria is given by P = −1718t2 + 82,000t + 10,000, where t is the time in hours since the culture was started. Determine the time(s) at which the population was 600,000. Round to the nearest hour.

Rounding to the nearest hour, the times at which the population was 600,000 was at 9 hours and at 39 hours.

Step-by-step explanation:

Determine the time(s) at which the population was 600,000.

This is t for which P(t) = 600000. To do this, we solve a quadratic equation.

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

.

This polynomial has roots such that , given by the following formulas:

In this question:

We have to find t for which P(t) = 600000. Then

So

Then

Rounding to the nearest hour, the times at which the population was 600,000 was at 9 hours and at 39 hours.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

3 qrs + 3/2 xy hope this : /

step-by-step explanation: