Find the equation of the line passing through the point (6,3) that is perpendicular to the line 4x−5y=−10. Enter your answers below. Use a forward slash (i. e. "/") for fractions (e. g. 1/2 for 12). Solution Step 1: Find the slope of the line 4x−5y=−10. Use a forward slash (i. e. "/") for all fractions (e. g. 1/2 for 12). m= What would the perpendicular slope be? m= Step 2: Use the slope to find the y-intercept of the perpendicular line. b= Step 3: Write the equation of the line that passes through the point (6,3) that is perpendicular to the line 4x−5y=−10 y= x+ Answer

Point - Slope Form: (y - 3) = -5/4(x - 6)

Slope - Intercept Form: y = -5/4x + 10.5

Step-by-step explanation:

Rewrite: y = 4/5x + 2

I don't know what the rest is but I'll do it in two forms:

Point - Slope Form:

Slope = -5/4

(y - 3) = -5/4(x - 6)

Slope - Intercept Form:

y = -5/4x + b

3 = -7.5 + b

b = 10.5

y = -5/4x + 10.5

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

answer: its the third option.

step-by-step explanation:

i just took the test.