An insurance institute conducted tests with crashes of new cars traveling at 6 mi/h. The total cost of the damages was found for a simple random sample of the tested cars and listed below. Find the (a) mean, (b) median, (c) mode, and (d) midrange for the given sample data. Do the different measures of center differ very much? $7 comma 402 $4 comma 819 $8 comma 969 $6 comma 275 $4 comma 326

a. Mean = $6,358.2

b. median = $6,275

c. Mode = none

d. Midrange = $6,647.5

There is no much difference in the measures of center.

Step-by-step explanation:

==>Given:

$7,402, $4,819, $8,969, $6,275, $4,326

==>Required:

a. Mean: sum of all values in the given sample data ÷ number of values in the sample

Mean = ($7,402 + $4,819 + $8,969 + $6,275 + $4,326) ÷ 5

= $31,791 ÷ 5

Mean = $6,358.2

b. Median: this is the meddle value if the data set when ordered. Ordering the data set, we have:

$4,326, $4819, [$6,275], $7402, $8,969

Our median is $6,275.

c. Mode is the most common value in the data set. Therefore, we have no mode since there is no value in our data set that appears the most.

d. Mid-range = (highest value + lowest value) ÷ 2

= ($8,969 + $4,326) ÷ 2

= 13,295 ÷ 2 = $6,647.5

i'm not entirely sure

step-by-step explanation:

if you ask home depot or lowe's they might be able to you out

let y equal to

the total fare and x is the mile of taxi ride. so the equation is

y = 0.55x + 1.75

since susie has

$10 to spend for a taxi cab, so he can have

10 = 0.55x +

1.75

x = 15 miles of

taxi ride

so the system of

inequality is

10 < 0.55x +

1.75

x > 2