Express x^2+4x-7 in the form (x+a)^2-b where a and b are integers

Here, we are required to express x² + 4x - 7 in the form (x+a)² - b and determine the values of a and b.

By completing the square method;

a = (4/2) = 2.

Therefore, by expanding (x+a)² i.e (x+2)²

We therefore have; x² + 4x + 4

However, the question is given as x²+4x-7

Therefore, by comparison between;

x² + 4x + 4 and x²+4x-7; we have;

4 - b = -7, b = 7+4

Ultimately, b = 11

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(x + 2)^2 - 11.

Step-by-step explanation:

f(x) = x^2 + 4x - 7

Now x^2 + 4x = (x + 2)^2 - 4 so we have:

f(x) = (x + 2)^2 - 4 - 7

f(x) = (x + 2)^2 - 11.

step-by-step explanation:

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x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15