Factor this polynomial completely over the set of complex numbers: f(x)=x^3-x^2-4x+4 Pleaseee answer asap! Thanks!

f(x)=(x-1)(x+2)(x-2) over all it equals to zero

(x-1) (x-2) (x+2)

Step-by-step explanation:

1. Factorice x^2 y -4 de la expresion.

x^2(x-1) -4(x-1)

2. Luego, debemos de factorizar x-1 de la expresion.

(x-1)(x^2 -4)

3. Usando a^2 - b^2= (a-b)(a+b) factorice la expresion.

(x-1) (x-2) (x+2)

d

step-by-step explanation:

by observation, we can see that the the graph is simply the graph of y = |x| that has been shifted 4 units downwards and 3 units to the left.

we can recognize in choice d :

y = | x + 3 |   - 4 (rewriting in general form)

y = | x - (- 3) |   - 4

the "-4 " term means   that the graph has been shifted by 4 units in the negative y direction

the "-3 " term means   that the graph has been shifted by 3 units in the negative x direction

this matches our observation of the graph described above.

answer: answer is c!

ok i got to organize the

3/15 and 12/55

3*

aha

3*4 equals 12 but not

a: no

b:

8/24 12/35

no

gautie

it's c

5/18 = 25/90

5*5=25

18*5 = 90

hope that you!

one more happy customer!

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step-by-step explanation: