Two parallel lines are crossed by a transversal. Horizontal and parallel lines p and q are cut by transversal m. At the intersection of lines p and m, the bottom left angle is b degrees. At the intersection of lines q and m, the top right angle is 128 degrees. What is the value of b?

If two parallel lines are cut by a transversal, then the pairs of consecutive interior angles formed are supplementary . ... When two lines are cut by a transversal, the pairs of angles on either side of the transversal and outside the two lines are called the alternate exterior angles .

Step-by-step explanation:

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The answer is 102

Step-by-step explanation:

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10 b/c 5*2 =10

step-by-step explanation:

the equation of the parallel line would be y = 2x + 9

step-by-step explanation:

to start we need to find the slope of the original line. we can do that by looking at the coefficient of x, which is 2

since the slope of the original line is 2 and parallel lines have the same slope, we know the new line will also have 2 slope. now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 5 = 2(x + 2)

y - 5 = 2x + 4

y = 2x + 9