Abdul drove four trips that totalled 426 km. The second trip was 4 less than double the first. The third trip was double the second and the fourth trip was 18 more than triple the first. How far was each trip? Please help!!!

Let the first trip be x

Second trip is 2x-4

Third trip is 2(2x-4)

Fourth trip is 3x + 18

x + (2x-4) + 2(2x-4)+3x+18 = 426

x + 2x -4 + 4x - 8 + 3x + 18 = 426

10x + 6 = 426

10x = 426-6

x = 420/10 = 42 km

Second trip was

2x-4 = 2(42)-4 = 84-4 = 80 km

Third trip was

2 * 80 = 160 km

Fourth trip was

3(42) + 18 = 144 km

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step-by-step explanation:

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

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