Please help me answer these two questions:) Find two consecutive numbers with a sum of 143. The combined mass of two children is 75 lbs. The first child is four times the mass of the second child. What are the masses of the two children? Whoever answers and explains i will give the brainliest!

Question 1: 71 and 72

Question 2: Child 1: 60 lbs, Child 2: 15 lbs

Step-by-step explanation:

Question 1:

Consecutive numbers are 2 numbers right next to each other.

You know the numbers will have to be double digits number.

71 and 72 are consecutive numbers. The sum of them is 143.

71+72=143

Question 2:

For this problem, we can use system of equations to find the mass of the 2 children. Let's say x is the first child and y is the second child.

Equation 1

x+y=75

This equation comes from the combined mass of the 2 children.

Equation 2

x=4y

This equation comes from the first child being 4 times the mass of the second child.

Since we know the value of x, we can use substitution to find y.

4y+y=75

5y=75

y=15

Now that we know the second child is 15 lbs, we can plug this into any of the 2 equations to find the mass of the first child.

x=4(15)

x=60

answer: the answer is (b) amie should have multiplied

step-by-step explanation: given a sphere and a cylinder with same radius and height.

let, 'r' be the radius of the cylinder and sphere and 'h' be the height of the cylinder. according to the question,

r = h.

now, the volume of the sphere will be

and the volume of the cylinder will be

therefore, we have

thus, ammie should have multiplied the volume of the sphere

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3