All equation of motion with examples

Answer is below. Hope this helps you!

Step-by-step explanation:

(i)v = u + at

(ii) s = ut + 1/2 *at²

(iii)2as = v²-u²

Examples:

A train starting from rest attains a velocity of 72km/h in 5 minutes. Assuming that the acceleration is uniform, find (i) the acceleration and  (ii)  the distance travelled by the train for attaining this velocity.

72km/h = 20m/s

(i) use v= u+ at

20 = 0 + a*300

20 = 5a

20 / 300= a

1/15 ms² = a

to find distance

use 2as= v²-u²

2 *1/15 * s = (20) - 0²

2/15s = 400

s = 400 * 15/2

s = 3000m = 3 km

a car accelerates with a uniform acceleration of 1m/s². it starts with a  velocity of 18km/h and reaches 36 km/h in 5 seconds find the distance travelled.

18 km /h = 5m/s

36km/h = 10m/s

use - s= ut + 1/2at²

s = 5 * 5 + 1/2 * 1 * (5)²

s = 25 + 25/2

s = 37.5 meters

b. x- 48 =120

step-by-step explanation: