A triangle has vertices at B(−3, 0), C(2, −1), D(−1, 2). Which transformation would produce an image with vertices B″(1, −2), C″(0, 3), D″(3, 0)? (x, y) → (x + 1, y + 1), (x, y) → (y, x)
(x, y) → (x + 1, y + 1), (x, y) → (−x, y),
(x, y) → (x, −y), (x, y) → (x + 2, y + 2)
(x, y) → (−x, y), (x, y) → (x + 2, y + 2)

(x, y) -> (x + 1, y + 1), (x, y) -> (y, x)

Step-by-step explanation:

I'll use point B (-3,0) for this problem.

First, the translation rule tells us to add 1 to the x value and add 1 to the y value. Now we have (-2, 1). Next, the rule tells us to flip the x and y coordinates. Now we have (1, -2). This matches to vertex B''(1, -2).

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.

step-by-step explanation: