In the diagram below of circle o, chords AB and CD intersect at E. If CE = 10, ED = 6, and AE = 4, what is the length of EB?

AWARDING MAX POINTS

The length of EB is found 15

Step-by-step explanation:

As the diagram of the circle is not given in the question, I've found the diagram of the same question from internet and attached below. So that we can have a better understanding)

We can see in the diagram the chord AB and chord CD intersect each other at point E.

Each of the chord is divided into two segments.

According to the Intersecting Chords Theorem:

Products of the lengths of line segments on each chord are equal

Which means that

(AE)(EB) = (CE)(ED)

Substitute the given values;

(4)(EB) = (10)(6)

4(EB) = 60

EB = 15

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72