Please help me is greatly appreciated

x = 3, x = 4

for all the three fill in the blanks.

Step-by-step explanation:

given

m(x) = (2x-6)(x-4)

given

m(x) = 0

thus

(2x-6)(x-4) = 0

it is possible when

either (2x-6) = 0   or (x-4) = 0

as 0 * any number = 0

thus,

2x-6 = 0

=> 2x = 6

=> x = 6/2 = 3

x- 4  = 0

x = 4

Thus , for first question

x = 3, x = 4

In the second problem, we have to find point on x axis where graph m intersects it.

it will happen when y = 0 , as when y is 0 , then point lies on x axis

we know that y = m(x)

thus, m(x) should be equal to 0

m(x) = (2x-6)(x-4) = 0

Again it will solved as above and value of x will be same as found above

x = 3, x = 4

Given that zeroes of function are where m(x) = 0

m(x) = (2x-6)(x-4) = 0

Again it will solved as solved in the first problem and value of x will be same as found above

x = 3, x = 4

what are the options? ?

step-by-step explanation:

step-by-step explanation: