A 50 ft kite string is flying on the beach above an umbrella. You are holding the end of the string and are 12 feet from the umbrella. How high in the air is the kite flying?
Round to the nearest degree.

The height of the kite is 48.54 feet

The angle of elevation is 76.11°

Step-by-step explanation:

To find the height of the kite, we can use the Pythagoras' theorem in the triangle created by the length of the string (hypotenuse), the height of the kite and the distance to the umbrella (catheti).

Then, we have:

50^2 = 12^2 + height^2

height^2 = 2500 - 144

height^2 = 2356

height = 48.54 ft

So the kite is 48.54 feet high in the air.

The angle of elevation can be calculated using the cosine relation:

cos(angle) = 12 / 50

cos(angle) = 0.24

angle = 76.11°

12

step-by-step explanation:

a triangle's   full angle is 180 degrees so 180 - 156 = 24. 24/2=12

explanation:

infrared radiation has wavelength in the range between 700 nm and 1 mm. lets' convert these values into scientific notation, keeping in mind that:

let's start from the lower value, we have:

(we moved the dot two places to the left, so we increased the exponent by 2 units, from -9 to -7)

the higher value is:

so, the range of wavelength of infrared radiation is: