I dont understand B and C in this question so there are a deck of cards 1-10 i already got A right but B and C i dont understand B: what is the probability of choosing a card that has a digit 1 on it
C: what is the probability that does not have a digit 1 on it? give both answers as a fraction here are the numbers to help
1 2 3 4 5 6 7 8 9 10

see below

Step-by-step explanation:

1 2 3 4 5 6 7 8 9 10  = 10 cards

9 of them have 1 digit on them  ( 10 has 2 digits)

P( 1 digit) = number with 1 digit) / total = 9/10

P(  not have 1 digit)= number not  with 1 digit) / total = 1/10

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.

there would only be 50 odd numbers between 1 and 100 so therefor there would be 50 even so that would only be 50 odd numbers.