How do i solve these trigonometric ?

find all solutions in the interval [0, 2π).

(sin x)(cos x) = 0

find all solutions in the interval [0, 2π).

cos2x + 2 cos x + 1 = 0

find all solutions to the equation.

cos2x + 2 cos x + 1 = 0

Solution are

i)

Step-by-step explanation:

1) (sinx)(cosx) =0

sin2x/2 =0

2x =0, 2pi, 3pi, 4pi

Hence

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2)

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hi there! my name is zalgo and i am here to you out today. the answer is pretty simple (in a way). this equation equals to 25.2!

i hope this answer !

"stay and stay proud! " - zalgo

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !