WILL MARK BRAINLIEST!! Lorri took a 240 km trip to Waterloo. On her way there, her average speed was 120 km/h. She was stopped for speeding, so on her way home, her average speed was 80 km/h. What was her average speed, in km/h, for the entire round-trip?

Her average speed was 480 km/ 5h which is 96.

Step-by-step explanation: When she went there her speed 120 km/ h and if the distance was 240 km, then it took her 2 hours to get there. 240 divided by 120 is 2. When she returned her average speed was 80 km/h and since the distance was 240, 240 divided by 8 is 3 which means it took her 3 hours to get back home. She drove a total of 480 km , because the distance to the trip was 240 and the distance from the trip to the back was 240. 240 + 240 is 480. She drove a total of 480 km in 5 hours because it took her 2 hours to go there and 3 hours to come back . 480 km / 5h

v = 1/3 a^2h

step-by-step explanation:

the volume is 1/3 a^2h.

when functions are first introduced, you will probably have some simplistic "functions" and relations to deal with, usually being just sets of points. these won't be terribly useful or interesting functions and relations, but your text wants you to get the idea of what the domain and range of a function are. small sets of points are generally the simplest sorts of relations, so your book starts with those.

step-by-step explanation:

state the domain and range of the following relation. is the relation a function?

{(2, –3), (4, 6), (3, –1), (6, 6), (2, 3)}

the above list of points, being a relationship between certain x's and certain y's, is a relation. the domain is all the x-values, and the range is all the y-values. to give the domain and the range, i just list the values without duplication:

domain: {2, 3, 4, 6}

range: {–3, –1, 3, 6}

(it is customary to list these values in numerical order, but it is not required. sets are called "unordered lists", so you can list the numbers in any order you feel like. just don't duplicate: technically, repetitions are okay in sets, but most instructors would count off for this.)

while the given set does indeed represent a relation (because x's and y's are being related to each other), the set they gave me contains two points with the same x-value: (2, –3) and (2, 3). since x = 2 gives me two possible destinations (that is, two possible y-values), then this relation is not a function.

note that all i had to do to check whether the relation was a function was to look for duplicate x-values. if you find any duplicate x-values, then the different y-values mean that you do not have a function. remember: for a relation to be a function, each x-value has to go to one, and only one, y-value.

state the domain and range of the following relation. is the relation a function?

{(–3, 5), (–2, 5), (–1, 5), (0, 5), (1, 5), (2, 5)}

i'll just list the x-values for the domain and the y-values for the range: