The average of four numbers is 38, and the average of the first two numbers is 42, and the average of the last three numbers is 36. What is the second number?

40

Step-by-step explanation:

let the numbers be a+b+c+d.

the average of 4 numbers is 38

; (a+b+c+d)/4 = 38

(a+b+c+d) = 152 equ1

the average of the first two numbers is 42

; (a+b)/2 = 42

(a+b) = 84 equ2

the average of the last three numbers is 36

; (b+c+d)/3 = 36

(b+c+d) = 108 equ3

substitute equ3 into equ1

a + 108 = 152

a= 152 - 108

a = 44

input the value of a into equ2

44 + b = 84

b = 40

the second number is 40.

I hope this helps.

225x²+4=0

225x²=0-4

225x²=-4

x²=-4/225

x=±√-4/225

10/60

step-by-step explanation:

if you divide 10 by 60 the answer is 0.166666 while if you divide or solve the other problems it equals 0.6