Prove that the difference between squares of consecutive even numbers is always a multiple of 4. Note: Let n stand for any integer in your working. Total marks: 4

see explanation

Step-by-step explanation:

consecutive even numbers have a difference of 2

let the consecutive even numbers be n and n + 2, thus

(n + 2)² - n² ← expand (n + 2)² using FOIL

= n² + 4n + 4 - n² ← collect like terms

= 4n + 4

= 4(n + 1) ← which results in a multiple of 4

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.

teleportation

step-by-step explanation: