In quadrilateral ABCD, AD ∥ BC. Quadrilateral A B C D is shown. Sides A D and B C are parallel. The length of A D is 3 x + 7 and the length of B C is 5 x minus 9. What must the length of segment AD be for the quadrilateral to be a parallelogram? 8 units 16 units 31 units 62 unitsIn quadrilateral ABCD, AD ∥ BC. 9.

  31 units

Step-by-step explanation:

When the figure is a parallelogram, opposite sides have the same measure:

  AD = BC

  3x +7 = 5x -9 . . . . . . substitute given expressions

  16 = 2x . . . . . . . . . . . add 9-3x

  8 = x . . . . . . . . . . . . . divide by 2

Use this value of x in the expression for AD to find its required length:

  AD = 3(8) +7 = 24 +7

  AD = 31 . . . . units

The length of segment AD must be 31 units for ABCD to be a parallelogram.

b

step-by-step explanation:

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true