The line passing through points(2,4) parallel to line who’s equation is Y equals X

The equation of that line is y = x + 2

Step-by-step explanation:

Here, we want to write the equation of the line that passes through the point given.

Now for the line which is our reference, we have the equation as;

y = x

Comparing this with the general equation of a straight line which is y = mx + c

where m is the slope, we can clearly see that the slope of that line is 1

Now if two lines are parallel, that surely do have equal slopes.

This means that the line that passes through that point also have a slope of 1

So we want to find the equation of a line with slope 1 and passing through the point (2,4)

What we use here is the point-slope form

Mathematically, that is

y-y1 = m(x-x1)

where (x1,y1) here is (2,4)

Thus, the equation of the line would be;

y-4 = 1(x-2)

y-4 = x-2

y = x-2+ 4

y = x+ 2

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.

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step-by-step explanation: