Consider a sampling distribution with p equals 0.11 and samples of size n each. Using the appropriate formulas, find the mean and the standard deviation of the sampling distribution of the sample proportion. a. For a random sample of size n equals 5000. b. For a random sample of size n equals 1000. c. For a random sample of size n equals 250.

a) Mean 0.11 and standard deviation 0.0044.

b) Mean 0.11 and standard deviation 0.0099.

c) Mean 0.11 and standard deviation 0.0198

Step-by-step explanation:

Central Limit Theorem:

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean and standard deviation

In this question:

a. For a random sample of size n equals 5000.

Mean:

Standard deviation:

Mean 0.11 and standard deviation 0.0044.

b. For a random sample of size n equals 1000.

Mean:

Standard deviation:

Mean 0.11 and standard deviation 0.0099.

c. For a random sample of size n equals 250.

Mean:

Standard deviation:

Mean 0.11 and standard deviation 0.0198

0.84 dang lotta people are looking for this lol or if you round up its 1 but the overall answer to that is 0.84

step-by-step explanation:

42%

step-by-step explanation:

we know,

total people = 60

total males = 25

percentage of males

= 25/60 × 100

= 25/6 × 10

= 25/3 × 5

= 125 / 3

= 41.

rounding of = 42%

happy to

pls mark as brainliest