A quadrilateral has verticies A(11,-7), B(9,-4), C(11,-1), and D(13, -4). Quadrilateral ABCD is a. if the vertex c(11,-1) were shifted to the point C(11,-1), quadrilateral ABCD would be a.

the answer is 14ft

step-by-step explanation:

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )

10 b/c 5*2 =10

step-by-step explanation: