The graph of f(x) is shown below. On a coordinate plane, a straight line has a negative slope and goes through (0, 6) and (3, 0). If f(x) and its inverse function, f Superscript negative 1 Baseline (x), are both plotted on the same coordinate plane, where is their point of intersection? (0,6) (1,4) (2,2) (3,0)

The intersection point is (2,2)

Step-by-step explanation:

First let's find the equation of f(x), using the linear model:

Using the point (0, 6), we have:

Using the point (3, 0), we have:

So we have that

To find f'(x) (the inverse of f(x)), we can substitute f(x) by x and x by f'(x) in the equation of f(x) and then isolate f'(x):

Now, to find the intersection point, we need to calculate f(x) = f'(x):

And the y-value is:

So the point is (2,2)

given hc ∥ gd.¯¯¯¯¯¯which statement is true

step-by-step explanation:

∠cbe and ∠deb are same-side interior angles

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116