Write an equation for the nth term of the given geometric sequence
-12,-36,-108...an

nth term of the geometric sequence

an= -12*3^(n-1)

Step-by-step explanation:

First term

a= -12

Second term

ar= -36

-12r=-36

r=-36/-12

=3

Third term

ar^2= -108

-12(3)^2

= -12(9)

= -108

nth term of the geometric sequence

an=ar^(n-1)

= -12*3^(n-1)

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!