[TIMED]
please help :( !

x = - 1 and x = 5

Step-by-step explanation:

Given

(x - 3)² + 2(x - 3) - 8 = 0

let u = x - 3 , then

u² + 2u - 8 = 0 ← in standard form

(u + 4)(u - 2) = 0 ← in factored form

Equate each factor to zero and solve for u

u + 4 = 0 ⇒ u = - 4

u - 2 = 0 ⇒ u = 2

Change these solutions for u back into solutions for x

u = x - 3 ( add 3 to both sides )

x = u + 3 , thus

u = - 4 → x = - 4 + 3 = - 1

u = 2 → x = 2 + 3 = 5

Solutions are x = - 1 and x = 5

x=5,-1

Step-by-step explanation:

x(x-3)-3(x-3)+2x-6-8=0

x2-3x-3x+9+2x-14=0

x2-4x-5=0

x2+x-5x-5=0

x(x+1)-5(x+1)=0

(X-5)(x+1)

X=5,-1