Determine whether b can be written as a linear combination of Bold a Subscript Bold 1a1, Bold a Subscript Bold 2a2, and Bold a Subscript Bold 3a3. In other words, determine whether weights x 1x1, x 2x2, and x 3x3 exist, such that x 1x1Bold a Subscript Bold 1a1plus+x 2x2Bold a Subscript Bold 2a2plus+x 3x3Bold a Subscript Bold 3a3equals=b. Determine the weights x 1x1, x 2x2, and x 3x3 if possible.

Complete  Question

The complete question is shown on the first uploaded image

 a

    b can be written as a linear combination of  

b

   The values of  

Step-by-step explanation:

From the question we are told that

Where ,   and  

   So  

=>  

=>  

=>  

Now multiplying equation 1 by 3 and adding the product to equation 2

=>        

 substituting into equation 1

Now to test substitute into equation 3

Since LHS = RHS then there exist values  such that

Hence b can be written as a linear combination of  

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.

the formula of a slope:

from a table we have

substitute:

the slope of f(x) is -1.

the graph of funcfion g(x) is a horizontal line. the slope of a horizontal line is equal 0. therefore the slope of g(x) is 0.

-1 < 0