The sum of the two numbers is 49 and the difference is 11. What are the numbers?

30,19

Step-by-step explanation:

let the numbers be x and y,x>y

x+y=49

x-y=11

add

2x=60

x=60/2=30

30+y=49

y=49-30=19

x = first number = 30 and y = second number = 19

Step-by-step explanation:

let the first number be x and second number be y.

According to the given information

The sum of the two numbers is 49

Here, we get the equation.

x + y = 49

Now, Similarly second given information

the difference is 11.

Here, we get the equation.

x - y = 11

Now,

Step 1:

Name the equations

x + y = 49 ...(1)

x - y = 11 ...(2)

Step 2:

Now,

From equation (1) we get,

x = 49 - y

Substitute the value of x = 49 - y in equation (2) we get,

x - y = 11

i.e.,

49 - y - y = 11

49 - 2y = 11

-2y + 49 = 11

2y - 49 = - 11

2y = 49 - 11

2y = 38

y = 38/2

y = 19

Step 3:

Now,

Put the value of y = 19 in equation (1), we get.

x + y = 49

i.e.,

x + 19 = 49

x = 49 - 19

x = 30

Thus, The value of x = first number = 30 and y = second number = 19

30 + 19 = 49

30 - 19 = 11

y > 1/3x

y < = -x + 4

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