Edmond doubled the width of the crate. How do the perimeter and the area of the floor of the new crate compare to those of the original crate? Original:length = 1.2 metres width = 0.8 metres

The area would be doubled also

The perimeter will be increased in a factor of 1.4

Step-by-step explanation:

Originally the area of new crate = L * B = 1.2 * 0.8 = 0.96 m^2

perimeter is 2(L+ B) = 2(1.2 + 0.8) = 4 m

Now let’s double the width , it becomes 0.8 * 2 = 1.6 m

Area would be 1.6 * 1.2 = 1.92 m^2 which is two times the previous area

The increased perimeter will be 2(1.6 + 1.2) = 5.6 m

This is an increase in factor of 1.4

i pretty sure it is

(a) the volume of the cone is 20/3 in3

hence, option a is correct.