The graph of F(x) shown below has the same shape as the graph of G(x)=x^3-x^2 but it is shifted to the left one unit. What is its equation? HELP PLEASE!!

Correct option: D

Step-by-step explanation:

If we want to shift the graph one unit to the left, we need to add one in the argument of the function, that is, we need to find G(x+1), and we do that by switching the values of x by (x+1) in the equation G(x)

So we have that:

G(x) = x^3 - x^2

Switching all values of x by x+1, we have:

G(x+1) = (x+1)^3 - (x+1)^2

So the correct option is D.

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

the expected value of the random variable : 0, 1 and 2

step-by-step explanation: