HEL Lisa is framing a rectangular painting length more than twice the widthShe uses 30 inches of framing material. What the length of the paintingWrite equation and solve.

A.3w+3=30;21

b.3w+3=30;9

C.6w+6=30;11

D.6w + 6 = 30 = 4

complete question:

Lisa is framing a rectangular painting. The length is three more than twice the width. She uses 30 inches of framing material. What is the length of the printing? Write an equation and solve

D.6w + 6 = 30 = 4

Step-by-step explanation:

perimeter = 30 inches

width = w

length = 2w + 3

perimeter of a rectangle = 2l + 2w

where

w = width

l = length

Therefore,

perimeter of a rectangle = 2(2w + 3) + 2w

perimeter of the rectangle = 4w + 6 + 2w

perimeter = 6w + 6

recall

perimeter = 30 inches

6w + 6 = 30

6w = 24

divide both sides by 6

w = 24/6

w = 4

step-by-step explanation:

there are 36 inches in a yard

25 : 36 = 0.69 yards (you can round to 0.70)

answer: y=0 if that is what u r looking for