Please help me :) once again

About 11.31 cm

Step-by-step explanation:

If one of the legs of a right iscosceles triangle is 8, then the length of the other one must also be 8. Therefore, by the Pythagorean Theorem:

Hope this helps!

Solution,

Hypotenuse=?

Perpendicular=8 cm

Base=8cm

Now,

Using Pythagoras theorem,

h^2=p^2+b^2

or,h^2=(8)^2+(8)^2

or,h^2=64+64

or,h^2=128

or,h=√128

or,h=8√2

h=11.31 cm

hope it helps

Good luck on your assignment

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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