Triangle PQR was dilated according to the rule DO,2(x, y)(2x,2y) to create similar triangle P'Q'Q. On a coordinate plane, (0, 0) is the center of dilation. Triangle P Q R is dilated to create triangle P Q prime Q. Triangle P Q R has points (negative 2, 2), (negative 2, 4), and (negative 1, 2). Triangle P prime Q prime Q has points (negative 4, 4), (negative 4, 8), and (negative 2, 4). Which statements are true? Select two options. ∠R corresponds to ∠P'QQ'. ∠PQR corresponds to ∠QPQ'. Segment QQ' is parallel to segment PP'. Side RQ corresponds to side QQ'. △PQR ≅ △P'Q'Q

i second the answers 1 (∠R corresponds to ∠P'QQ') & 4 (Side RQ corresponds to side QQ')

Step-by-step explanation:

e d g e 2020

have a good day bruvs :)

1 and 4. got it right edu2020.

Step-by-step explanation:

Triangle PQR was dilated according to the rule  DO,2(x,y)(2x,2y) to create similar triangle P'Q'Q.

On a coordinate plane, (0, 0) is the center of dilation. Triangle P Q R is dilated to create triangle P Q prime Q. Triangle P Q R has points (negative 2, 2), (negative 2, 4), and (negative 1, 2). Triangle P prime Q prime Q has points (negative 4, 4), (negative 4, 8), and (negative 2, 4).

Which statements are true? Select two options.

∠R corresponds to ∠P'QQ'.

∠PQR corresponds to ∠QPQ'.

Segment QQ' is parallel to segment PP'.

Side RQ corresponds to side QQ'.

△PQR ≅ △P'Q'Q

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

you'll just earn points here

step-by-step explanation: