Determine the discriminant for the quadratic equation -3=x^2+4x+1. Based on the discriminant value, how many real number solutions does the equation have ? Discriminant value = b^2-4ac

One real root (multiplicity 2).

Step-by-step explanation:

-3=x^2+4x+1

x^2 + 4x + 4 = 0

Discriminant = 4^2 - 4*1*4 = 0

There is one real root (multiplicity 2).

The equation has 1 real solution.

The quadratic function is given as:

Add 3 to both sides of the equation

This gives

Rewrite the equation as:

A quadratic equation is represented as:

By comparison, we have:

The discriminant (d) is calculated as:

So, we have:

Evaluate like terms

Given that the discriminant value is 0, it means that the equation has 1 real solution.

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y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead