I'm needing some with number 13 and 14.

13.  What you want to do is solve for X.  However, you need to create an equation that will let you do this.

First, we know the measures of each of the angles (sort of)

ZST=X+120

RST=136

RSZ=X+36

Because angle RSZ is "inside of" or "contained in" angle RST, angle RSZ + angle ZST = angle RST.

Since we know the values of all of these, we can create our equation.

RSZ + ZST = RST

(X+36) + (X+120) = 136

Now, because everything is addition, we can drop the parentheses.

X+36+X+120=136

Now, we add like terms.

X+X+36+120=136

2X+156=136

We now subtract and divide so that we can solve for X.

2X+156=136

2X+156-156=136-156

2X=-20

2X/2=-20/2

X=-10

Now that we have solved for X, we can solve for ZST.

ZST=X+120

ZST=(-10)+120

ZST=110°

I have to post this now, or the time will run out.  I will try #14 after posting this.

14. In the same way that RST "contained" the other two angles in 13, IJK contains the other two angles in this one. This means that you need to set IJK equal to the other two angles.

AJK+IJA=IJK

44+(2X+16)=9X-10

Now, to solve for X, we get all of the X's on one side.

44+(2X+16)=9X-10

44+2X+16=9X-10

44+16+2X-9X=9X-9X-10

44+16-7X=-10

60-7X=-10

Now we subtract 60 from both sides to get X by itself.

60-60-7X=-10-60

-7X=-70

We can now divide by -7 to solve for X.

(-7X)/(-7)=(-50)/(-7)

X=+70/7

X=10

Now we can substitute X for 10 and solve for IJK.

IJK=9X-10

IJK=[9(10)]-10

IJK=(90)-10

IJK=80

Ais the correct answer