For a statistics class project, a college student randomly samples 75 men who exercise at a gym regularly and 68 women who exercise at a gym regularly. The college student believes that on average men spend more time at the gym each week. The college student records the number of minutes each person exercises in a given week. The college student conducts a hypothesis test at the 5% significance level. Use the summary statistics below to conduct a hypothesis test using your calculator or calculator

Step-by-step explanation:

The record of the statistics and the summary statistics which are the missing files in the question are attached below.

From the given information:

The null hypothesis and the alternative hypothesis can be represented by :

There is no difference between the average time  spend by men and women at gym each week

The average time  spend by men is greater than the average time spend by women at the gym each week

From the summary statistics in the attached file below:

The p-value = 0.3253

Level of significance = 5% = 0.05

Therefore; it is obvious that the p-value is greater than the level of significance  i.e (0.3253 > 0.05)

Hence; there is no enough evidence to reject the null hypothesis

CONCLUSION: We conclude that the mean number of minutes exercised per week is larger for men than women at the  this gym.

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )