Solve the equation sin2∅=2sin∅, domain 0°≤B≤360°

∅ = 90°

Step-by-step explanation:

Given;

sin2∅=2sin∅

sin2∅ = 2sin∅Cos∅

but, Sin²∅ + Cos²∅ = 1

       Cos²∅ = 1 - Sin²∅

       Cos ∅ = √(1 - Sin²∅)

sin2∅=2sin∅ ↓

2sin∅Cos∅ = 2sin∅

2sin∅(√(1 - Sin²∅)) = 2sin∅

Let Sin∅ = P

2P( √(1 - P²)) = 2P

Divide both sides by 2P

√(1 - P²) = 1

Square both sides

1 - P² = 1

P² = 1 - 1

P² = 0

P = 0

Recall, Sin∅ = P

Sin∅ = 0

∅ = Sin ⁻¹(0)

∅ = 90°

the range is 19

step-by-step explanation:

the range is biggest number minus the smallest, so in this case it would be

41 - 22 = 19