What is the equation of the line that passes through (4, -1) and (-2, 3)? 2 x+3y- 5 = 0
-2 x+3y- 5 = 0
2x-3y-5=0

Step-by-step explanation:

(3+1)/(-2-4)= 4/-6= -2/3

y + 1 = -2/3(x - 4)

y + 1 = -2/3x + 8/3

y = -2/3x + 5/3

Multiply both sides by 3

3y = -2x + 5

2x + 3y = 5

2x + 3y - 5 = 0

answer is A

the answer is c just got it on ed

step-by-step explanation:

2x^2+5x+17

your welcome. : )