PLEASE HURRY
Which equation of a line passes through the points (3,
-1) and (6, 1)?

To write the equation of line in y = mx + b form, we need

to identify the slope of the line and the y-intercept.

I would start by setting up a coordinate

system and plotting both points.

I have shown this below.

Let's start with our first point, (3, -1) which we call point A.

Now our second point, (6, 1) which we call point B.

To get from point A to point B, we rise 2 units and run 3 units.

So we know that our slope is 2/3.

However, we need the y-intercept.

Remember, this is the point where the line crosses the y-axis.

Since point B is farther from y-axis,

we need to go in the other direction.

So starting at point A, we go down 2 and to the left 3.

Remember, -2/-3 is 2/3 since a negative/negative = positive.

Now plot point C.

Notice that point C is on the y-axis.

It has the coordinates (0,-3).

Now we know our slope and y-intercept.

So our equation reads 2/3x - 3.

The slope is positive since the line is going up.

question: match the eqaution with its graph -8x - 5y = 40

answer: 8 x 5 = 40

x= absiss

y= orderly

so you have a proportional graph

question answered by

(jacemorris04)