The masses mi are located at the points Pi. Find the moments Mx and My and the center of mass of the system. m1 = 7, m2 = 6, m3=1, m4 = 5; P1(1,-2), P2(3,4), P3(-3,-7), P4(6,-1) Mx = 1
My = 2center of mass = ( 3, 4)

Y=-2x-6 is the answer

Answer: d. 39 cmin the diagram, the approximate length of the minor arc de is 39 centimetres.step-by-step explanation: the formula for the length of an arc in a circle is as displayed below.let the length of the minor arc de = xx = 2( pi )r × angle of sector / 360°from this, we will substitute the values given from the problem into the formula to obtain the length of the minor arc de.x = 2( pi )r × angle of sector / 360°r = radius = 25cmpi as an approximate value = 3.14angle of sector = 120°x = 2( 3.14 )( 25 ) × 120° / 360°x = 157 × 1 / 4x = 39.25x = 39 ( rounded to the nearest whole number as an approximate value )