Mary was told that a line goes through the points (1, 3) and (6, -2) and has a slope of 3. A. Explain why the information Mary was given cannot be correct. B. If the given point (1, 3) and the given slope are correct, what is the equation for the line? C. Give the coordinates of another point on the line. D. If the given points are correct on the line, what is the slope? E. Write an equation for the line.

Below in bold.

Step-by-step explanation:

A. We can calculate the slope using (y2 - y1) / (x2 - x1)

= (3 - (-2)) / (1 - 6)

=  5/-5

= -1.

So the given slope of 3 or one of the points is NOT correct.

B. If the point (1, 3 ) and the slope are correct then the equation  for the line  (using the point-slope form) is y - 3 = 3(x - 1)  

C Another point on this line would be , when x = 0 , y = 3*-1 + 3 = 0

so it's (0, 0)

D. If the given points are correct the slope is ( as above) =  -1.

E. The equation for this line is

y - 3 = -1(x - 1)

y = -x + 1 + 3

y = 4 - x.

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

given hc ∥ gd.¯¯¯¯¯¯which statement is true

step-by-step explanation:

∠cbe and ∠deb are same-side interior angles