Phonics is an instructional method in which children are taught to connect sounds with letters or groups of letters. A sample of 134 first-graders who were learning English were asked to identify as many letter sounds as possible in a period of one minute. The average number of letter sounds identified was 34.06 with a standard deviation of 23.83. a. Construct a 98% confidence interval for the mean number of letter sounds identified in one minute.
b. If a 95% confidence interval were constructed with these data, would it be wider or narrower than the interval constructed in part (a)? Explain.

a)    

b) For this case since the confidence level decrease then the confidence interval would decrease respect a) also since the margin of error would be lower.

Step-by-step explanation:

Information given

represent the sample mean

population mean (variable of interest)

s=23.83 represent the sample standard deviation

n=134 represent the sample size  

Part a

The confidence interval for the mean is given by the following formula:

  (1)

The degrees of freedom are given:

The Confidence level is 0.98 or 98%, the value of significance is and ,  and the critical value would be

Replacing we got:

Part b

For this case since the confidence level decrease then the confidence interval would decrease respect a) also since the margin of error would be lower.

50 min

step-by-step explanation:

they will be decreasing both their times in half

60 / 2 = 30

40/2 = 20

30 + 20 = 50

answer: c

because if you look at the chart you can see a pattern and compare it to the question he simplify out your

but i think the formula is f(x)=6x