If you’re good with permutations in math 30 please help and answer this easy question below real answers only a graduating class has 10 students with 6 boys and 4 girls. the number of ways the students can be arranged in a line if the girls must be together and the boys must be together is

a) 2(6!)(4!)

b) 10!

c) 6!4!

d) 2 (6) (4!)

 a) 2(6!)(4!)

Step-by-step explanation:

The number of ways the boys can be arranged is: 6!

The number of ways the girls can be arranged is: 4!

The number of ways the groups (boys & girls) can be arranged is: 2

Girls could be in the front .. or in the back ... of the line.

Put these together to get: 6! × 4! × 2

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

step-by-step explanation: